December 26, 2010

December 25, 2010

[SOLVED] Android: no adb on Suse linux or "???????????? no permissions"

You cant develop on your linux pc because you are getting something like this.
$ adb devices
List of devices attached
???????????? no permissions

temporary solution - to restart adb server as root
$ su
$ adb kill-server
$ adb start-server
$ adb devices

add your device to devices list.
1) check your vendor ID
$ lsusb
Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub
Bus 002 Device 044: ID 18d1:2d66 <- this is my mobile
Bus 002 Device 004: ID 0451:2046 Texas Instruments, Inc. TUSB2046 Hub
Bus 002 Device 003: ID 10d5:0001 Uni Class Technology Co., Ltd

In my case , for Nexus One, it is 18d1

2) now add lines in to "/etc/udev/rules.d/51-android.rules"
$ su
$ vim /etc/udev/rules.d/51-android.rules

now paste these lines with your values
SUBSYSTEM=="usb", SYSFS{idVendor}=="18d1", MODE="0666"

save your file.

now it should work...


December 14, 2010

[SOLVED] Unix: search files between TIME1 and TIME2 with string 123456 in it


TIME1 = 2010-11-02 00:00
TIME2 = 2010-11-24 00:00
File pattern "PATTERN1231313123.txt"

create files with right timestamps
 touch -t 11020000 /tmp/stamp_2010-11-02_0000
touch -t 11240000 /tmp/stamp_2010-11-24_0000

check your list of files if it is right
find . -regextype posix-awk  -regex '^\./PREFIX[0-9]*.txt' -newer /tmp/stamp_2010-11-02_0000 -and -not -newer /tmp/stamp_2010-11-24_0000 -ls

export your list
 find . -regextype posix-awk  -regex '^\./PREFIX[0-9]*.txt' -newer /tmp/stamp_2010-11-02_0000 -and -not -newer /tmp/stamp_2010-11-24_0000 -exec grep --color "123456" {} \; > /tmp/mydata_123456.csv


December 13, 2010

[SOLVED] Android: Multiple substitutions specified in non-positional format

Getting an error after updating to SDK 0.8
Multiple substitutions specified in non-positional format; did you mean to add the formatted="false" attribute? strings.xml

It happens in string files on strings with %
	"%s/%s (Linux; Android)"

You should change it to
	"%1$s/%2$s (Linux; Android)"


December 9, 2010

[SOLVED] PHP: Why 2 !=2 aka "never compare floating point numbers for equality"

“never compare floating point numbers for equality”.

The reason (19.6*100) !== (double)1960, is because inside a computer they are not equal.

Try this:


printf("%.15f", (19.6*100));


Outputs: 1960.000000000000227 (not 1960 as somewhat expected)

If comparison is required a few options come to mind (other than BCMath):

1) Round numbers before comparison:


$sig_figs = 5;
echo (round((19.6*100), $sig_figs) !== round((double)1960, $sig_figs)) ? 'not equal' : 'equal';


Outputs: equal